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Maths for electricians · Topic 3 of 6

Areas, circles and π

About 3 minutes · Diagrams, worked examples and a mini test

Cable sizes are areas: 2.5 mm² is the cross-sectional area of the copper. Floor areas decide how many socket circuits you need. So area comes up all the time.

Rectangles and triangles

  • Rectangle: area = length × width. A 4 m × 5 m room is 20 m².
  • Triangle: area = ½ × base × height. A gable wall 6 m wide and 4 m high is 12 m².

Circles and π

A circle showing the radius, from the centre to the edge, and the diameter, straight across through the centre. The diameter is twice the radius. Area equals pi times radius squared. diameter dr Area = πr²= πd² ÷ 4Circumference = πdπ ≈ 3.142

π (pi) is the number of times a circle's diameter fits round its edge: about 3.142. Use the π key on your calculator.

  • Area = π × r², or π × d² ÷ 4 if you know the diameter.
  • Circumference (distance round) = π × d.

Worked example: a 2.5 mm² conductor

A solid 2.5 mm² conductor is about 1.78 mm across. Its area is π × 1.78² ÷ 4 = π × 3.17 ÷ 4 = 2.49 mm², which rounds to 2.5 mm².

Going the other way, the diameter is d = √(4 × A ÷ π). For 6 mm²: √(24 ÷ π) = 2.76 mm.

Converting area units

Because area is two lengths multiplied, the conversion is squared too: 1 m = 1,000 mm, so 1 m² = 1,000 × 1,000 = 1,000,000 mm².

Exam tip: check whether a question gives the radius or the diameter. Using the diameter in πr² makes the answer four times too big.

Mini test

Pick an answer to see if you're right and why.